3x^2+4=296

Solution for 3x^2+4=296 equation:

3x^2+4=296

We move all terms to the left:

3x^2+4-(296)=0

We add all the numbers together, and all the variables

3x^2-292=0

a = 3; b = 0; c = -292;
Δ = b2-4ac
Δ = 02-4·3·(-292)
Δ = 3504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3504}=\sqrt{16*219}=\sqrt{16}*\sqrt{219}=4\sqrt{219}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{219}}{2*3}=\frac{0-4\sqrt{219}}{6}
=-\frac{4\sqrt{219}}{6}
=-\frac{2\sqrt{219}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{219}}{2*3}=\frac{0+4\sqrt{219}}{6}
=\frac{4\sqrt{219}}{6}
=\frac{2\sqrt{219}}{3}
$